Question

Find the difference. (2x^2 - 3x + 7) - (x^2 + 6x - 12)A)

A) x^2 + 3x - 5


B) x^2 - 3x + 19


C) x^2 - 6x + 12


D) x^2 - 9x + 19

Answer 1

Its D.

(2x^2 - 3x + 7) - (x^2 + 6x - 12)

Distribute the negative over the second parentheses:-

= (2x^2 - 3x + 7) - x^2 - 6x + 12

= x^2 - 9x + 19 (answer)