Question

Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches the average basketball player is 79 inches tall approximately what percent of the adult male population is taller than the average basketball player

Answer 1

Answer: 0.135

Step-by-step explanation:

Answer 2

your correct answer should be: z = (x - mean) / SD = (79 - 70) / 3 = 3

P (Z > 3)? = 1 - F (z) = 1 - F (3) = 0.00135 i hope this is helpful! :D