Question

PLEASE HELP ME QUESTION 7

Answer 1

The image shows the following:

• adjacent = 6
• opposite = 8 (use Pythagorean Theorem)
• hypotenuse = 10

adjacent² + opposite² = hypotenuse²

6² + opposite² = 10²

36 + opposite² = 100

opposite² = 64

opposite = 8

sin =
`(opposite)/(hypotenuse)` =
`(8)/(10)` =
`(4)/(5)` reduced

cos =
`(adjacent)/(hypotenuse)` =
`(6)/(10)` =
`(3)/(5)` reduced

tan =
`(opposite)/(adjacent)` =
`(8)/(6)` =
`(4)/(3)` reduced

csc =
`(hypotenuse)/(opposite)` =
`(10)/(8)` =
`(5)/(4)` reduced

sec =
`(hypotenuse)/(adjacent)` =
`(10)/(6)` =
`(5)/(3)` reduced

cot =
`(adjacent)/(opposite)` =
`(6)/(8)` =
`(3)/(4)` reduced