asked 31.2k views
2 votes
What is the product of d - 9 and 2d^2+11d-4

2 Answers

3 votes

Answer:

2d^3-7d^2-103d+36

Explanation:

(d-9)(2d^2+11d-4)

2d^3+11d^2-4d-18d^2-99d+36

2d^3+11d^2-18d^2-4d-99d+36

2d^3-7d^2-103d+36

answered
User Jonthornham
by
8.6k points
6 votes

(d - 9) · (2d² + 11d - 4)

First distribute the "d" into (2d² + 11d - 4), then distribute -9 into (2d² + 11d - 4)

2d³ + 11d² - 4d - 18d² - 99d + 36

2d³ - 7d² - 103d + 36

answered
User Farrukh Najmi
by
8.1k points

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