Question

Find the vertex of the parabola whose equation is y=x2+6x+2

Answer 1

The vertex of the parabola
`y=ax^2+bx+c` has the coordinates:

• 
  `x_v=-(b)/(2a);`
• 
  `y_v=ax_v^2+bx_v+c.`

Therfore, the vertex of the parabola
`y=x^2+6x+2` has coordinates

`x_v=-(6)/(2)=-3`

and

`y_v=(-3)^2+6\cdot (-3)+2=9-18+2=-7.`

Answer: (-3,-7)