Question

Which is the equation in point-slope form of the line that contains points A and E?

Answer 1

Point-slope form:
`y-4=(3)/(4)(x-4)`

Explanation:

We are given some points on coordinate plane.

We need to find the equation of line in point slope form which passes through A and E

First we write the coordinate of point A and Point E

Point A: (-4,-2)

Point E: (4,4)

Formula:

`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

`y-4=(-2-4)/(-4-4)(x-4)`

`y-4=(3)/(4)(x-4)`

where,

`slope=(3)/(4)`

Hence, The slope point form of line is
`y-4=(3)/(4)(x-4)`

Answer 2

y+2 = 3/4(x+4)

or with the other point

y-4 = 3/4 (x-4)

Explanation:

We can find the slope of the line since we have 2 points

A(-4,-2) and E(4,4)

m = (y2-y1)/(x2-x1)

= (4--2)/(4--4)

= (4+2)/(4+4)

=6/8

= 3/4

Then we can use point slope form

y-y1 = m(x-x1)

y--2 = 3/4 (x--4)

y+2 = 3/4(x+4)

or with the other point

y-4 = 3/4 (x-4)