Question

Can someone answer for me please.

the hypotenuse of a 45o -45o -90o triangle measures 10 square root of 5 what is the length of one leg of the triangle?

Answer 1

check the picture below.

now, let's rationalize the denominator on that.

`\bf \cfrac{10√(5)}{√(2)}\implies \cfrac{10√(5)}{√(2)}\cdot \cfrac{√(2)}{√(2)}\implies \cfrac{10√(5)\cdot √(2)}{(√(2))^2}\implies \cfrac{10√(5\cdot 2)}{2}\implies 5√(10)`