Question

Whlch set of numbers contains both solutions to the equation x2 - 2x - 8 = 0?

Answer 1

Answer: x = {-2, 4}

Explanation:

0 = x² - 2x - 8

∧

1 -8 = -7

2 -4 = -2 This works because the b-value is -2!

0 = (x + 2)(x - 4)

0 = x + 2 0 = x - 4

x = -2 x = 4