Question

An object accelerated from rest with a constant acceleration of 5.2 m/s^2, what will its velocity be after 3 s

Answer 1

Answer: The velocity after 3 s will be
`15.6(m)/(s)`

Step-by-step explanation:

Since the initial velocity v0 is zero:

`v(t) = at + v_0 = at\\v(3) = 3a = 3\cdot5.2 (s\cdot m)/(s^2)= 15.6(m)/(s)\\`