Question

What is the reactance of a 25 mF capacitor when the applied frequency is 400 Hz?

Answer 1

The capacitive reactance is 15.92Ω.

Solution-

We know that,

`X_c=(1)/(2\pi fC)`

Where,

`X_c` = Capacitive Reactance (in Ω)

f = frequency (in Hz)

C = Capacitance (in F)

Here given,

`X_c` = ??

f = 400 Hz

C = 25 mF =
`25* 10^(-6)` F

Putting the values in the formula,

`X_c=(1)/(2\pi * 400* 25* 10^(-6))`

`X_c=(10^(6))/(20000\pi)`

`X_c=15.92\ \Omega`

Therefore, the capacitive reactance is 15.92Ω.