Question

What is the reactance of a 25 mF capacitor when the applied frequency is 400 Hz?

Answer 1

The Reactance of a Capacitor is the resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. This is measured in ohms (Ω) and its formula is:

`X_(C)=(1)/(2\pi fC)` (1)

Where:

`X_(C)` is the Reactance in ohms (Ω)

`f` is the frequency of the alternating current in Hertz (
`Hz`)

`C` is the Capacitance of the Capacitor in Farad (
`F`)

In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.

Note
`1mF=1*10^(-3)F=0.001F`

Well, with the given data we have to solve (1):

`X_(C)=(1)/(2\pi(400Hz)(25*10^(-3)F))`

Then:

XC=0.0159 Ω This is the Reactance of the Capacitor