Answer:
The value of sin Ф is 
 
Explanation:
In quadrant II, the value of 
Let us solve the question
∵ sin²Ф + cos²Ф = 1
∵ cos Ф = 

→ Substitute it in the identity above
∴ sin²Ф + (
)² = 1
∴ sin²Ф + 
 = 1
→ Subtract 
 from both sides
∵ sin²Ф + 
 - 
 = 1 - 
 
∴ sin²Ф = 
 
→ Take the square root of both sides
∵ √(sin²Ф)= ± 

∴ sin Ф = ± 

∵ Ф is in quadrant II
∴ sin Ф is a positive value
∴ sin Ф = 

∴ The value of sin Ф is