Question

If n = 8 and 16 · 2^m = 4^(n – 8), then m = ?

F. –4
G. –2
H. 0
J. 1
K. 8

Answer 1

16 · 2^m = 4^(n – 8)

get everything with the same base)

2^4 * 2^m = 2^2^(n-8)

2^(4+m) = 2^(2(n-8))

4+m = 2(n-8)

4+m =2n-16

m =2n-16-4

if n=8

m =2n-20

m =16-20

m=-4

Choice F