Find the illegal values of b in the fraction.

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asked Nov 6, 2019 98.0k views

1 Answer

Chinh Phan · Answer 1 · 2019-11-12T12:48:43+0000

Denominator can't be zero, so:

b^2 - 2b - 8 = 0
b^2 - 4b + 2b - 8 = 0
b(b-4) + 2(b-4) = 0
(b-4) (b+2) = 0

b-4 = 0
b = 4

b+2 = 0
b = -2

b can't be equal to 4 and -2

Answer: D

Find the illegal values of b in the fraction.

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