Question

I need to solve for p and have a rationalized denominator

Answer 1

`p = \pm (√(r(st - 1)))/(st - 1)`

or

`p = (√(r(st - 1)))/(st - 1)`

Explanation:

`t = (p^2 + r)/(p^2s)`

`p^2st = p^2 + r`

`p^2st - p^2 = r`

`p^2(st - 1) = r`

`p^2 = (r)/(st - 1)`

`p = \pm \sqrt{(r)/(st - 1)}`

Your picture cuts out the assumption. If the assumption is that all variables are non-negative, then the answer is

`p = \sqrt{(r)/(st - 1)}`

`p = (√(r))/(√(st - 1))}`

`p = (√(r))/(√(st - 1))} * (√(st - 1))/(√(st - 1))`

`p = (√(r) √(st - 1))/(√(st - 1)√(st - 1))`

`p = (√(r(st - 1)))/(st - 1)`