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The height above the ground (in feet) of a ball dropped from the top of a 30-foot-tall building after t seconds is given by the polynomial − 16t^2 + 30 . What is the height of the ball after 1/2 second?

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The height h above ground in feet of a ball dropped from the top of a 30 foot tall building after t seconds is given by the polynomial: h(t)= -16t^2+30. what is the height of the ball after 1/2 second?

h(t)= -16t^2+30

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Sub 1/2 for t to find h(1/2)

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User Marco Biscaro
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