asked 18.7k views
3 votes
Find 3 consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen

asked
User MichaelB
by
8.2k points

1 Answer

4 votes

Answer:

The three consecutive odd integers are 3,5,7

How:

Let x, (x+2),(x+4) represent the three consecutive odd integers

Question states***

2[x + (x+4)] = (x+2) + 15

solving for s

4x + 8 = x + 17

3x = 9

x = 3 The three consecutive odd integers are 3,5,7




answered
User Mwjackson
by
7.9k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.