Question

I need to solve for x using the pythagorean theorem some how (I think) please only answer if you can give a hint or the answer with an explanation.

Answer 1

`\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies √(c^2-a^2)=b \qquad \begin{cases} c=\stackrel{hypotenuse}{\stackrel{3959+5.9}{3964.9}}\\ a=\stackrel{adjacent}{3959}\\ b=\stackrel{opposite}{x}\\ \end{cases} \\\\\\ √(3964.9^2-3959^2)=x\implies √(46751.01)=x\implies 216.22\approx x`

Answer 2

Explanation:

Formula

a^2 + b^2 = c^2

Remark

The horizon point is where x and 3959 meet.

Givens

a = 3959

b = x

c =3959 + 5.9 = 3964.9

Solution

3959^2 + x^2 = 3964.9 ^2

15673681 + x^2 = 15720432.01 Subtract 15673681 from both sides

x^2 = 15720432.01 - 15673681 Combine

x^2 =46751.01 Take the square root of both sides

sqrt(x^2) = sqrt(46751.01)

x = 216.2

If you round anywhere but at the end, an error will creep in that will make your answer incorrect.