Question

Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50

Answer 1

`f(2)= 6x^4-10x^3+40x-50=46`

Solution-

The given function is,

`\Rightarrow f(x)= 6x^4-10x^3+40x-50`

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

`\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50`

`\Rightarrow f(2)= (6* 16)-(10* 8)+(40* 2)-50`

`\Rightarrow f(2)= (6* 16)-(10* 8)+(40* 2)-50`

`\Rightarrow f(2)= 96-80+80-50`

`\Rightarrow f(2)= 96-50`

`\Rightarrow f(2)= 46`

Therefore, f(2) was found to be 46.