Question

Write y=x^2+4x-5 in vertex form. Then identify the vertex.

Answer 1

Vertex Form: y = (x+2)^2 - 9

Vertex : (-2,-9)

Explanation:

First, we need to use the -b/2a formula to find the x value or the axis of symmetry.

-4/2 = -2

Now we have that, we have our x-coordinate. Now we need to find our y variable. We have to plug the x value into the equation.

-2^2 + 4(-2) - 5

+ 4 - 8 - 5

- 4 - 5

-9

Now that we have our coordinates, we have our vertex.

(-2,-9)

Now we have to convert it to vertex form.

Vertex Form: y = a(x-h)^2 + k

y = 1(x--2)^2 + (-9)

y = 1(x+2)^2 - 9

Answer 2

the vertex form is (x+2)^2 - 9 and the vertex is (-2, -9)