Question

a sample of methane gas at a pressure of 0.815 atm and a temperature of 265 C occupies a volume of 416 mL. If the gas is heated at constant pressure until its volume is 593 ml the temperature of the gas will be _________ C

Answer 1

493.9°C

Step-by-step explanation:

Given parameters:

Initial pressure =0.815atm

Initial temperature = 265C = 265 + 273 = 538k

Initial volume = 416mL = 0.416L

New volume = 593mL = 0.593L

Unknown:

New temperature =?

Solution:

Since we are dealing with constant pressure condition, we apply charles's law.

It states that the volume of a fixed mass of gas varies directly as its absolute temperature if the pressure is constant.

Mathematically ;

`(V1)/(T1)` =
`(V2)/(T2)`

V1 is the initial volume V2 is the new volume

T1 is the initial temperature T2 is the new temperature

`(0.416)/(538)` =
`(0.593)/(T2)`

T2 = 766.9K;

In °C = 766.9 - 273 = 493.9°C