3. An acute angle θ is in a right triangle with cos θ = two thirds . What is the value of sec θ? (2 points) five divided by two two divided by square root of five square root of…

Question

asked Jan 3, 2019 8.3k views

1 Answer

Pask · Answer 1 · 2019-01-08T05:14:49+0000

Answer: sec θ =
(3)/(2)

Explanation:

cos θ =
(adjacent)/(hypotenuse) =
(2)/(3)

sec θ =
(hypotenuse)/(adjacent) =
(3)/(2)

Extra Credit: Use Pythagorean Theorem to find the opposite side

2² + b² = 3²

4 + b² = 9

b² = 5

b = √5

sin θ =
(opposite)/(hypotenuse) =
(√(5))/(3)

csc θ =
(hypotenuse)/(opposite) =
(3)/(√(5)) =
(3√(5))/(5)}