asked 91.5k views
5 votes
What is the sum of 3b(b-4) and 6(b-8)?

asked
User Fivef
by
7.6k points

2 Answers

3 votes

3b^2 - 6b +36.

3b^2 - 6b +36.

answered
User Marius Seack
by
7.2k points
4 votes

Answer:

3b² -6b -48

Explanation:

Given : 3b(b-4) and 6(b-8).

To find : What is the sum.

Solution : We have given 3b(b-4) and 6(b-8).

According to question :

3b(b-4) + 6(b-8).

Distribute 3b over b-4 and 6 over b-8.

3b² -12b + 6b -48.

Combine like terms.

3b² -6b -48.

Therefore,3b² -6b -48.

answered
User David Locke
by
7.7k points

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