Question

What are the roots of f(x)= x^2-48

Answer 1

x1=4\sqrt{3}

x2=-4\sqrt{3}

Explanation:

f(x) = 0\iff x^2-48=0 \. 4.1. 36 votes ... To find the roots equate the function to zero ... x^{2}=48. Step 2. Take the square root of both sides. \sqrt{x^{2}}= \sqrt{48} ... If GI bisects m (2x-23)=ghi (4x-29)=gfi A. 21 B. 23 C. 42 D. 46.

Answer 2

4Sqrt3, -4sqrt3

Step-by-step explanation: sqrt stand for square root :)