Question

What is the pressure exerted by 0.703 mol o2 in a 15.0 l container at 314 k. express your answer in atmospheres?

Answer 1

This question is based on the ideal gas law
`PV=nRT`, where
`P` is the pressure,
`V` is the volume,
`n` is number of moles,
`R` is the gas constant which can take many values depending on the units. In this problem we will use
`0.082057Latmmol^-^1K^-^1` to get our pressure in atm. So we male P the subject of the formula

`P=(nRT)/(V)= ((0.703*0.08205*314))/(15)=(18.11)/(15)= 1.2atm`