asked 57.1k views
2 votes
Which equation represents a circle with a center at (2, –8) and a radius of 11?

asked
User Fisher
by
8.6k points

2 Answers

2 votes

Answer:

(x-2)^2 + (y+8)^2 = 11^2

Explanation:

The standard equation of a circle with center at (h,k) and radius r is

(x-h)^2 + (y-k)^2 = r^2.

Filling in the given info, we get:

(x-2)^2 + (y+8)^2 = 11^2

answered
User Mark Lopez
by
8.0k points
3 votes

(x-h)^2 +(y-k)^2 = r^2 is the equation for a circle centered at (h,k) and radius r

(x-2)^2 +(y- (-8))^2 = 11^2

(x-2)^2 +(y+8)^2 = 11^2

Answer:(x-2)^2 +(y+8)^2 = 11^2

answered
User Humkins
by
8.6k points

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