Register

A ball is thrown vertically upwards. After t seconds, his height (in feet) is given by the function h(t)=104t-16t^2. After how long will it reach its maximum height?

A ball is thrown vertically upwards. After t seconds, his height (in feet) is given by the function h(t)=104t-16t^2. After how long will it reach its maximum height?
asked 67.0k views
0 votes
A ball is thrown vertically upwards. After t seconds, his height (in feet) is given by the function h(t)=104t-16t^2. After how long will it reach its maximum height?

asked
User Leansy
by
8.3k points

1 Answer

3 votes


104t-16t^2=-16(t^2-6.5t+10.5625-10.5625)=-16(t-3.25)+169


At t= 2.5 seconds it will reach the maximum height 169 m..

answered
User Belyash
by
9.1k points
← Prev Question Next Question →

Related questions

User JonLim
asked Nov 25, 2020 93.0k views
H=-16t^2 + 104t + 56​
JonLim asked Nov 25, 2020
by JonLim
8.4k points
1 answer
4 votes
93.0k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!