Question

Calculate the pH of a solution that has a [OH−] of 2.6 × 10^−6 M.

A. 8.4
B. 6.5
C. 7.7
D. 6.29

Answer 1

A. 8.4

Explanation:

[OH⁻] = 2.6 × 10⁻⁶ Take the negative log of each side

-log[OH⁻] = pOH = 5.59 Apply the pH/pOH relation

pH + pOH = 14.00 Insert the value of pOH

pH + 5.59 = 14.00 Subtract 5.59 from each side

pH = 14.00 -5.59 = 8.41