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What is x^2-12x+23=7 in vertex form?

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User Azabella
by
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1 Answer

2 votes

Answer:

y = (x - 6)^2 - 20

Explanation:

Let's start by completing the square for x^2 - 12x. Half of the coefficient of x is (1/2)(-12), or -6. Square this and add it to x^2 - 12x, and then subtract it:

x^2 - 12x + 36 - 36 + 23 = 7

Rewriting the first three terms,

(x - 6)^2 -13 = 7, or

y = (x - 6)^2 - 20

The vertex is located at (h,k), which here is (6, -20).

answered
User Mukul Bansal
by
7.4k points

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