An isosceles right triangle whose legs are 6 is rotated about one of its legs to generate a right circular cone. What is the volume of the cone?

Question

asked Nov 1, 2019 109k views

1 Answer

Frinux · Answer 1 · 2019-11-04T23:23:58+0000

Answer:

$V = 72 \pi$

Explanation:

The radius of the base is one of the legs, so it is 6.

The height of the cone is the other leg, so it is also 6.

$V = (1)/(3) \pi r^2 h$

$V = (1)/(3) (\pi)(6^2)(6)$

$V = (\pi)(36)(2)$

$V = 72 \pi$