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8<2/3(3y-6) 8 \leqslant (2)/(3) (3y - 6)

8<2/3(3y-6) 8 \leqslant (2)/(3) (3y - 6)
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3 votes
8<2/3(3y-6)

8 \leqslant (2)/(3) (3y - 6)

asked
User Zac
by
8.7k points

1 Answer

6 votes

8<=2/3(3y-6)

distribute

8<= 2y -4

add 4 to each side

12 <=2y

divide by 2

6<=y

answered
User Iago
by
7.6k points
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