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Find the real or imaginary solution of each equation by factoring.

2x^2+3=4x

1 Answer

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2x^2+3=4x \\\\2x^2-4x+3=0\\\\\Delta=(-4)^2-4\cdot2\cdot3=16-24=8\\\\√(\Delta)=\sqrt8=2\sqrt2\\\\x_1=(-(-4)-2\sqrt2)/(2\cdot2)=(2-\sqrt2)/(2)\\\\x_2=(-(-4)+2\sqrt2)/(2\cdot2)=(2+\sqrt2)/(2)

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User Jakie
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