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Solve: f - 6 < 5 AND f - 4 > (or equal to) 2

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User Dkubb
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\bf \begin{cases} f-6<5\implies &amp;f<11 \\\\\ f-4\ge 2\implies &amp;f\ge 6 \end{cases} ~\hspace{5em}\stackrel{\textit{and we can also write it as triplet}}{6\le f < 11}

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User Ketrox
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