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3x^2-n-4y^2=(3x-y)(x+4y),n=? NEED HELP ASAP

F.11xy
G.-11xy
H.13xy
J.-13xy

1 Answer

4 votes

Answer:

n = -11xy, so the answer is G.

Explanation:

3x^2−n−4y^2=(3x−y)(x+4y)

Step 1: Add -3x^2 to both sides.

3x^2−4y^2−n+−3x^2=3x^2+11xy−4y^2+−3x^2

−4y^2−n=11xy−4y^2

Step 2: Add 4y^2 to both sides.

−4y^2−n+4y^2=11xy−4y^2+4y^2

−n=11xy

Step 3: Divide both sides by -1.

n=−11xy

answered
User Max Williams
by
8.6k points
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