1. The sum of 122 and 98 is (122+98)
Two-thirds of the sum of 122 and 98 is

2. 99 divided by 10 is
The sum of 84 and 3 is (84+3).
99 divided by 10, then multiplied by the sum of 84 and 3 is

3. (10+5)=15,
1=+53=63.
Since 15<63, then (10+5)<10+53.
4. (16-4)+9=12+9=21,
(16-4)=12.
Since 21>12, then (16-4)+9>(16-4).