asked 197k views
2 votes
Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be used.

Roy and Elisa are buying tickets for the annual school concert. Roy buys 6 adult tickets and 2 child tickets for a total of $66. Elisa buys 5 adult tickets and 4 child tickets for a total of $62.

Determine the system of equations that can be used to find the cost of one adult ticket, a, and the cost of one child ticket, c.


8 5 4 62 2 6 128 66
roy __a + __c=__
elisa __a + __c=__

asked
User Xtds
by
7.6k points

2 Answers

5 votes

Answer:

roy 6a + 2c = 66 elisa 5a + 4c = 62

Explanation:

hope this helps

answered
User Jodi
by
7.2k points
3 votes

We are given :

The cost of one adult ticket = a.

The cost of one child ticket = c.

Roy buys

6 adult tickets and 2 child tickets.

Total amount = $66.

Therefore, first equation for Roy total amount would be

6a +2c = 66 --------------------(1)

Elisa buys

5 adult tickets and 4 child tickets.

Total amount = $62.

Therefore, second equation for Elisa total amount would be

5a +4c = 62 --------------------(1).

Therefore,

Roy 6a + 2c = 66

Elisa 5a + 4c = 62.



answered
User Ryan Duffield
by
8.8k points
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