Question

If the temperature remains constant and the initial pressure is 101.3 kpa then what is the new pressure reading when the volume is doubled

Answer 1

50.65 kPa

Step-by-step explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

`p_(1)V_(1) = p_(2)V_(2)`

We can solve this equation to get

`p_(2) = p_(1) * (V_(1))/( V_(2))`

`p_(1) = \text{101.3 kPa}; V_(1) = V_(1)`

`p_(2) = ?; V_(2) = 2V_(1)`

`p_(2) = \text{101.3 kPa} * (V_(1))/(2V_(1)) = \textbf{50.65 kPa}`