Write the expression 3 log(x-2)+log(x+2)-log(x^2-4) as a single logarithm.

asked Feb 23, 2019 32.7k views

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$3 \log(x-2)+\log(x+2)-\log(x^2-4) = 3 \log ((x-2)(x+2))/((x^2-4))=\\=3 \log ((x^2-4))/((x^2-4))=3\log 1= \log 1^3 = \log 1 = 0$

to answer with a single logarithm: log 1, and the value is 0

Meta Fan answered Feb 27, 2019

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