Question

find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less then four times the smaller number.

Answer 1

N is an odd integer

The Next Larger is N+2

N+2 + 2N = -27 + 4N

3N + 2 = 4N - 27

0 = 4N - 27 - 3N - 2

0 = N - 29

N = 29

They are 29 and 31.

31 + 2(29) = 4(29) - 27

31 + 58 = 89 = 116 - 27 yes it works