Question

What is the possible arrangement for 22 students

Answer 1

`\bf \stackrel{Permutations}{_nP_r=\cfrac{n!}{(n-r)!}}~\hspace{6em}\stackrel{\textit{22 units arranged in groups of 22}}{_(22)P_(22)=\cfrac{22!}{(22-22)!}} \implies _(22)P_(22)=\cfrac{22!}{0!} \\\\\\ _(22)P_(22)=\cfrac{22!}{1}\implies _(22)P_(22)=22!\implies _(22)P_(22)=1124000727777607680000`