Question

The sum of two consecutive integers is –49. Write an equation that models this situation and find the values of the two integers.

n + n + 1 = –49; n = –25; n + 1 = –24
n + n + 1 = –49; n = –25; n + 1 = –26
n + 2n = –49; n = –17; 2n = –34
n + n + 1 = –49; n = –24; n + 1 = –23

Answer 1

The correct option n + n +1 = -49;n = -25; n + 1 = -24

Explanation:

Answer 2

The correct option is:
`n + n + 1 = -49; n = -25; n + 1 = -24`

Explanation:

Suppose, the first integer is
`n`

As the two integers are consecutive, so the second integer will be:
`n+1`

Given that, the sum of two integers is -49.

So, the equation will be.........

`n+(n+1)= -49\\ \\\Rightarrow 2n+1=-49\\ \\ \Rightarrow 2n=-50\\ \\ \Rightarrow n=(-50)/(2)=-25`

Thus, the first integer is,
`n= -25` and the second integer is,
`n+1= -25+1= -24`