Question

Find the axis of symmetry of 2x^2 + 12x + 16 Show your work

Answer 1

The vertex form:

`y=a(x-h)^2+k\\\\(h,\ k)-vertex`

The axis of symetry is x = h.

`y=ax^2+bx+c\to h=(-b)/(2a)`

We have

`y=2x^2+12x+16\to a=2,\ b=12,\ c=16`

Substitute:

`h=(-12)/((2)(2))=(-12)/(4)=-3`

Answer: x = -3