Question

How many milliliters of a 0.266 M RbNO3 solution are required to make 150.0 mL of 0.075 M RbNO3 solution? How many milliliters of a 0.266 M RbNO3 solution are required to make 150.0 mL of 0.075 M RbNO3 solution? 42.3 mL 53.2 mL 35.1 mL 18.8 mL 23.6 mL

Answer 1

Answer : 42.3 ml of a 0.266 M
`RbNO_3` solution are required.

Solution : Given,

Molarity of
`RbNO_3` solution 1 = 0.266 M

Molarity of
`RbNO_3` solution 2 = 0.075 M

Volume of
`RbNO_3` solution 2 = 150 ml = 0.150 L (1 L = 1000 ml)

Formula used :

`M_1V_1=M_2V_2`

where,

`M_1` = Molarity of
`RbNO_3` solution 1

`M_2` = Molarity of
`RbNO_3` solution 2

`V_1` = Volume of
`RbNO_3` solution 1

`V_2` = Volume of
`RbNO_3` solution 2

Now put all the given values in above formula, we get

`0.266M* V_1=0.075M* 0.150L\\V_1=0.042293L=42.293ml\approx 42.3 ml` (1 L = 1000 ml)

Therefore, 42.3 ml of a 0.266 M
`RbNO_3` solution are required.