Question

The area of the rectangle shown is at most of 140 square cm

Answer 1

x would be equal to or less than 4. It would not be possible for it to have a length of 15 because 15x10=150 and the maximum area is 140 sq cm.

Answer 2

Explanation:

Part A:

The length is given as =
`3x+2` cm

The width is give as = 10 cm

Area of rectangle = length x width

Area =
`(3x+2)10`

Given is that the area of the rectangle shown is at most of 140 square cm.

So, we can write this as:

`(3x+2)10 \leq140`

Solving this we get;

`30x+20 \leq140`

=>
`30x \leq140-20`

=>
`30x \leq120`

We get
`x \leq4`

So,
`3(4)+2` = 14 cm

Hence, the length can be 14 cm and width is 10 cm.

Part B:

No, it is not possible as if the length will be 15, it will give an area of 150 cm square that is greater than 140 cm square.