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Help me please. Please see attached for the questions with the graph

Help me please. Please see attached for the questions with the graph-example-1

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Answer

5) b-c

6) a-b and

e-f

7) f-g

9) a-b = 0 m/s

c-d = 0.6667 m/s

e-f = 0 m/s

f-g = -3 m/s

10) b-c ⇒ The cart is acceleration.

e-f ⇒ The cart is moving backwards with a constant velocity.

Step-by-step explanation

Answer

5) b-c

In the section b-c the cart is accelerating because the slope of the graph is changing. The gradient that represent velocity is increasing.

6) a-b and e-f

At this sections the distance is not changing at all. This can only mean that the cart is not moving. It is at rest.

7) f-g

At this section the slope is negative meaning the cart is moving back to where it came from.

9) a-b = 0 m/s

At a-b the cart is not moving. So the velocity is zero.

c-d = 0.66667 m/s

Velocity = distance / time

=(50-40)/(40-25)

= 10/15

= 0.6667 m/s

e-f = 0 m/s

At e-f the cart is not moving. So the velocity is zero.

f-g = -3 m/s

Velocity = distance / time

= (60-30)/(65-75)

= 30/-10

= - 3 m/s

10) b-c ⇒ The cart is acceleration.

e-f ⇒ The cart is moving backwards with a constant velocity.

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User Bscothern
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