asked 157k views
5 votes
each course at college x is worth either 3 or 4 credits the members of the swim team are taking a total of 49 courses that are worth a total of 161 credits

asked
User Ravindu
by
7.0k points

2 Answers

5 votes

To answer this problem, you should set up a system of inequalities to model the total number of courses and credits. This would look like:

x+y=49

3x+4y=161

where x is the 3 credit courses and y is the 4 credit courses.


There are many ways to solve system of equation, but this would best be solved by the substitution method. On the first equation, subtract x from both sides to get y=49-x. Now, since we know what y equals, when can substitute "49-x" for y in the second equation and solve for x.

3x+4(49-x)=161

*Use the distributive property*

3x+196-4x=161

*Combine like terms*

-x+196=161

*Subtract 196 from both sides*

-x=-35

*Divide both sides by -1*

x=35


Now, that we know that the swim team took 35 3 credit courses, we can solve for y using the first equation.

*Plug in 35 for x*

35+y=49

*Subtract 35 from both sides*

y=14


The swim team took 35 3 credit courses and 14 4 credit courses.


Hope this helps!


answered
User Martijn Visser
by
8.4k points
7 votes

x= number of credit courses

y = number of 4 credit courses

x+y = 49

solve for x

x=49-y

3x+4y=161

substitute x=49-y into above equation

3(49-y) +4y=161

distribute

147 -3y +4y=161

combine like terms

147+y=161

subtract 147 from each side

y=14

x=49-y

x=49-14

x=35

they took 35 3 credit courses and 14 4 credit courses

35*3+14*4 = 161 so it checks

subtract 147 from each side


answered
User Abhinav Goyal
by
7.8k points
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