Question

The width of a rectangle is 17 yd shorter than the length. The perimeter of the rectangle is 126 yd. Find the width of the rectangle.

Answer 1

We have been given that the width is 17 yd shorter than the length.

Therefore, w = l - 17

Also, the perimeter = 126 yd

2(l + w) = 126

l + w = 63

l + (l - 17) = 63

2l - 17 = 63

2l = 63 + 17

2l = 80

l = 40 yd

But, w = l - 17

w = 40 - 17

w = 23 yd.