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Find the area of a triangle having vertices at (-4,8); (3,-11); and (1,6)

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check the picture below.


so, we can simply split that triangle, intwo two triangles, as you see in the picture, the blue and yellow ones.

notice, the blue one has a height of 2, a base of 5, whilst the yellow one has a base of 5 and a height of 17.

now, we can simply get the area area of each triangle, add them up, and that's the area of that larger triangle.



\bf \stackrel{\textit{blue triangle's area}}{\cfrac{1}{2}(5)(2)}~~+~~\stackrel{\textit{yellow triangle's area}}{\cfrac{1}{2}(5)(17)}\implies 5+42.5\implies 47.5

Find the area of a triangle having vertices at (-4,8); (3,-11); and (1,6)-example-1
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User Seth Connell
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