asked 118k views
5 votes
When an object is dropped on the moon, it travels approximately

0.8t^2 meters in t seconds. Suppose an astronaut drops a moon rock from a height of 2 meters. Find the speed of the rock after 1 second.

1 Answer

3 votes

Answer:

1.6 meters per second.

Explanation:

We have been given an position function
P(t)=0.8t^(2) and we are asked to find the speed of the rock after 1 second.

Derivative of this function will give us speed function.


S(t)=2\cdot 0.8\cdot t


S(t)=1.6\cdot t

Now let us find derivative when t=1,


S(1)=1.6\cdot 1=1.6

Therefore, the speed of the rock after 1 second will be 1.6 meters per second.

answered
User H H
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.