Question

I need to solve for x

Answer 1

`BE=BD+DE=BC+CE\\\\BD=19,\ DE=5,\ BC=x+13,\ CE=x+15\\\\\text{substitute}\\\\19+5=(x+13)+(x+15)\\\\24=x+13+x+15\\\\24=2x+28\qquad|-28\\\\-4=2x\qquad|:2\\\\-2=x\to x=-2\\\\Answer:\ C)\ -2`